JEE Main 2019 — Physics solution

JEE Main2019Physics

A soap bubble, blown by a mechanical pump at the mouth of a tube, increases in volume, with time, at a constant rate. The graph that correctly depicts the time dependence of pressure inside the bubble is given by:

Solution

$V = c t \Rightarrow \frac{4}{3} π r^{3} = c t \Rightarrow r = k t^{1/3} P = P_{0} + \frac{4 T}{k t ^{1/3}} \Rightarrow P = P_{0} + c (\frac{1}{t ^{1/3}})$

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