In the above circuit, $C=\frac{\sqrt{3}}{2}$$\mu \text{F,}{\text{R}}_2=20\Omega$ , $L=\frac{\sqrt{3}}{10}$H and R₁ = 10 $\Omega$. Current in L-R₁ path is I₁ and in C–R₂ path it is I₂ . The voltage of A.C source is given by $V=200\sqrt{2}\sin \left(100t\right)$ volts. The phase difference between I₁ and I₂ is.