JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

Two particles move at right angle to each other. Their de Broglie wavelengths are $λ_{1}$ and $λ_{2}$ respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelength $λ$ , of the final particle, is given by:

A
$λ = λ_{1} λ_{2}$
B
$λ = \frac{λ _{1} + λ _{2}}{2}$
C
$\frac{2}{λ} = \frac{1}{λ _{1}} + \frac{1}{λ _{2}}$
D
$\frac{1}{λ ^{2}} = \frac{1}{λ _{1}^{2}} + \frac{1}{λ _{2}^{2}}$

Solution

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