JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

The integral $\int \frac{3 x ^{13} + 2 x ^{11}}{( 2 x ^{4} + 3 x ^{2} + 1 ) ^{4}} d x$ is equal to (where C is a constant of integration)

A
$\frac{x ^{4}}{6 ( 2 x ^{4} + 3 x ^{2} + 1 ) ^{3}} + C$
B
$\frac{x ^{12}}{( 2 x ^{4} + 3 x ^{2} + 1 ) ^{3}} + C$
C
$\frac{x ^{12}}{6 ( 2 x ^{4} + 3 x ^{2} + 1 ) ^{3}} + C$
D
$\frac{x ^{4}}{( 2 x ^{4} + 3 x ^{2} + 1 ) ^{3}} + C$

Solution

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