JEE Main2019Physics
Q.
The bob of a simple pendulum has mass 2 g and a charge of 5.0 C. It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium, the angle that the pendulum makes with the vertical is. (take g = 10 m/s2)
- A
tan–1 (0.2)
- B
tan–1 (5.0)
- C
tan–1 (2.0)
- D
tan–1 (0.5)
Solution

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