JEE Main 2019 — Physics solution

JEE Main2019Physics

A circular coil having N turns and radius r carries a current I. It is held in the XZ plane in a magnetic field B $\hat{i}$ . The torque on the coil due to the magnetic field is:

A
$\frac{B π r ^{2} I}{N}$
B
$\frac{B π ^{2} I}{π N}$
C
$B π r^{2} I N$
D
Zero

Solution

$τ = μ \times B = N I A \times B [A = π r^{2}] \Rightarrow τ = N I π r^{2} B$

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