JEE Main2019Chemistry
Q.
An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1 bar. The work done in kJ is :
- A
–9.0
- B
–0.9
- C
–2.0
- D
+10.0
Solution
w = –PV
= –( 1 bar) × (9 L)
= –(105 Pa) × (9 × 10–3) m3
= –9 × 102 N-m
= –900 J
= –0.9 kJ
Practice more Chemistry
Concept-wise practice with instant solutions on Fundamenthol.
Start practicing →