In the following reaction;

$\mathrm{xA}\to \mathrm{yB}$

$\mathrm{lo}{\mathrm{g}}_{10}\left[-\frac{\mathrm{d}\left(\mathrm{A}\right)}{\mathrm{dt}}\right]=\mathrm{lo}{\mathrm{g}}_{10}\left[\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{dt}}\right]+0.3010$

‘A’ and ‘B’ respectively can be :