JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.

One may conclude that :

A
$R (T) = \frac{R _{0}}{T ^{2}}$
B
$R (T) = R_{0} e^{- T_{0}^{2} / T^{2}}$
C
$R (T) = R_{0} e^{- T^{2} T_{0}^{2}}$
D
$R (T) = R_{0} e T^{2} / T_{0}^{2}$

Solution

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