JEE Main 2019 — Physics solution

JEE Main2019Physics

For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at $12 7^{\circ} C$ . At 2 atm pressure and at $22 7^{\circ} C$ , the rms speed of the molecules will be:

A
$1005 m / s$
B
$100 m / s$
C
$805 m / s$
D
$80 m / s$

Solution

$V \propto T \frac{V _{1}}{V _{2}} = \frac{T _{1}}{T _{2}} \frac{200}{V _{2}} = \frac{400}{500} V_{2} = 200 \frac{5}{4} = 1005 m / s$

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