JEE Main2019Math
Q.
Given that the slope of the tangent to a curve y = y(x) at any point (x,y) is . x If the curve passes through the centre of the circle x2 + y2 – 2x – 2y = 0, then its equation is
- A
x loge |y| = –2(x – 1)
- B
x loge |y| = x – 1
- C
x loge |y| = 2(x – 1)
- D
x2 loge |y| = – 2(x – 1)
Solution
