JEE Main 2019 — Physics solution

JEE Main2019Physics

A moving coil galvanometer has resistance $50 Ω$ and it indicates full deflection at 4 mA current. A voltmeter is made using this galvanometer and a $5 k Ω$ resistance. The maximum voltage, that can be measured using this voltmeter, will be close to:

A
10 V
B
20 V
C
15 V
D
40 V

Solution

$V = l_{g} (R_{s} + R_{g}) = 4 \times 1 0^{- 3} [5050] \approx 20 V$

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