JEE Main 2019 — Physics solution

JEE Main2019Physics

A moving coil galvanometer, having a resistance G, produces full scale deflection when a current I_g flows through it. This galvanometer can be converted into (i) an ammeter of range 0 to I₀ (I₀ > I_g ) by connecting a shunt resistance R_A to it and (ii) into a voltmeter of range 0 to V(V = GI₀) by connecting a series resistance R_V to it. Then,

A
$R_{A} R_{V} = G^{2}$ and $\frac{R _{A}}{R _{V}} = (\frac{I _{g}}{I _{0} - I _{g}})^{2}$
B
$R_{A} R_{V} = G^{2} (\frac{I _{g}}{I _{0} - I _{g}})^{2}$ and $\frac{R _{A}}{R _{V}} = (\frac{I _{0} - I _{g}}{I _{g}})^{2}$
C
$R_{A} R_{V} = G^{2}$ and $\frac{R _{A}}{R _{V}} = \frac{I _{g}}{( I _{0} - I _{g} )}$
D
$R_{A} R_{V} = G^{2} (\frac{( I _{0} - I _{g} )}{I _{g}})$ and $\frac{R _{A}}{R _{V}} = (\frac{I _{0}}{( I _{0} - I _{g} )})^{2}$

Solution

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