Fundamentholfundamenthol
JEE Main2019Physics
Q.

Taking the wavelength of first Balmer line in hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be : 

  1. A

    889.2 nm

  2. B

    488.9 nm

  3. C

    388.9 nm

  4. D

    642.7 nm

Solution

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