JEE Main 2019 — Physics solution

JEE Main2019Physics

A system of three charges are placed as shown in the figure :

If D >> d, the potential energy of the system is best given by :

Solution

$U = - \frac{K q ^{2}}{d} + Q V V = \frac{K P}{D ^{2}} = - \frac{K q d}{D ^{2}} U = - \frac{K q ^{2}}{d} - \frac{K Qq d}{D ^{2}}$

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.