JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

For an initial screening of an admission test, a candidate is given fifty problems to solve. If the probability that the candidate can solve any problem is $\frac{4}{5}$ then the probability that he is unable to solve less than two problems is:

A
$\frac{316}{25} (\frac{4}{5})^{48}$
B
$\frac{54}{5} (\frac{4}{5})^{49}$
C
$\frac{201}{5} (\frac{4}{5})^{49}$
D
$\frac{164}{25} (\frac{1}{5})^{48}$

Solution

← Back to full paper

Practice more Math

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →