Fundamentholfundamenthol
JEE Main2019Math
Q.

A value of (0, /3), for which  \left| {\begin{array}{*{20}{c}} {1 + {{\cos }^2}\theta }{{{\sin }^2}\theta }{4\cos 6\theta } \\ {{{\cos }^2}\theta }{1 + {{\sin }^2}\theta }{4\cos 6\theta } \\ {{{\cos }^2}\theta }{{{\sin }^2}\theta }{1 + 4\cos 6\theta } \end{array}} \right| = \,0, is

  1. A

           

  2. B

  3. C

  4. D

Solution

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