JEE Main2019Math
Q.
Let f(x) = ax (a > 0) be written as f(x) = f1(x) + f2(x), where f1(x) is an even function and f2(x) is an odd function. Then f1(x + y) + f1(x – y) equals :
- A
2f1(x)f1(y)
- B
2f1(x + y)f1(x – y)
- C
2f1(x + y)f2(x – y)
- D
2f1(x)f2(y)
Solution
