JEE Main2019MathQ.if ∫x3(1+x6)2/3dx=xf(x)(1+x6)1/3+C where C is a constant of integration, then the function f(x) is equal to:A−2x31Bx23C−6x31D−2x21SolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →