JEE Main2019Math
Q.
The equation of a common tangent to the curves, y2 = 16x and xy = –4, is :
- A
x + y + 4 = 0
- B
2x – y + 2 = 0
- C
x – 2y + 16 = 0
- D
x – y + 4 = 0
Solution

The equation of a common tangent to the curves, y2 = 16x and xy = –4, is :
x + y + 4 = 0
2x – y + 2 = 0
x – 2y + 16 = 0
x – y + 4 = 0
