JEE Main 2019 — Math solution

JEE Main2019Math

A triangle has a vertex at (1, 2) and the mid points of the two sides through it are (–1, 1) and (2, 3). Then the centroid of this triangle is :

Solution

Co-ordinates of vertex B and C are B(–3, 0) and C(3, 4)

$Centroid G (\frac{3 - 3 + 1}{3}, \frac{0 + 4 + 2}{3})$

$(\frac{3 - 3 + 1}{3}, \frac{0 + 4 + 2}{3}) G (\frac{1}{3}, 2)$

Practice more Math

Concept-wise practice with instant solutions on Fundamenthol.