JEE Main 2019 — Math solution

JEE Main2019Math

A straight line L at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to this line makes an angle of 60° with the line x + y = 0. Then an equation of the line L is :

A
( $3$ + 1)x + ( $3$ – 1)y = 8 $2$
B
$3$ x + y = 8
C
x + $3$ y = 8
D
( $3$ + 1)x + ( $3$ + 1)y = 7 $2$

Solution

If perpendicular makes an angle of 60° with the line x + y = 0.

Then the perpendicular makes an angle of 15° or 75° with x-axis. So the equation of line will be

xcos75° + ysin75° = 4 or xcos15° + ysin15° = 4

$(3 - 1) x + (3 + 1) y = 82 or$

$(3 + 1) x + (3 - 1) y = 82$

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