JEE Main2019MathQ.If ∫esecx(secxtanxf(x)+secxtanx+sec2x))dx=esecxf(x)+C, then a possible cohoice of f(x) is :Asecx−tanx−21Bsecx+tanx+21Csecx+tanx−21Dxsecx+tanx+21SolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →