JEE Main 2019 — Chemistry solution

JEE Main2019Chemistry

Molal depression constant for a solvent is 4.0 K kg mol^–1. The depression in the freezing point of the solvent for 0.03 mol kg^–1solution of K₂SO₄is. (Assume complete dissociation of the electrolyte)

A
0.36 K
B
0.18 K
C
0.12 K
D
0.24 K

Solution

$K_{2} S O_{4} \to 2 K^{+} + S O_{4}^{2 -}$

i (Van’t Hoff Factor) = 3

$∴ Δ T_{f} = i K_{f} m = 3 \times 4 \times 0.03 = 0.36 K$

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