JEE Main2019MathQ.The value of the integral 0∫1xcot−1(1−x2+x4)dx is :A4π−loge2B2π−loge2C2π−21loge2D4π−21loge2SolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →