JEE Main2019MathQ.If α and β are the roots of the quadratic equation, x2 + x sinθ – 2sinθ = 0, θ∈(0,2π),then (α−12+β−12).(α−β)24α12+β12 is equal to:A(sinθ−8)6212B(sinθ−4)12212C(sinθ+8)1226D(sinθ+8)12212SolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →