JEE Main2019MathQ.If y = y(x) is the solution of the differential equation dxdy=(tanx−y)sec2x,x∈(−2π,2π),such that y(0) = 0, then y(−4π)is equal to : Ae1−2B21−eCe−2D2+21SolutionView solution← Back to full paperPractice more MathConcept-wise practice with instant solutions on Fundamenthol.Start practicing →