JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

If $\int \frac{d x}{( x ^{2} - 2 x + 10 ) ^{2}}$ $= A (tan^{- 1} (\frac{x - 1}{3}) + \frac{f ( x )}{x ^{2} - 2 x + 10}) + C$

where C is a constant of integration, then :

A
$A = \frac{1}{81}$ and f(x)= 3(x -1)
B
$A = \frac{1}{54}$ and f(x) = 3(x -1)
C
$A = \frac{1}{27}$ and f(x) = 9(x -1)
D
$A = \frac{1}{54}$ and f(x)= 9(x- 1)²

Solution

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