JEE Main2019Math
Q.
If both the mean and the standard deviation of 50 observations x1, x2, ... x50 are equal to 16, then the mean of (x1 – 4)2, (x2 – 4)2, ... (x50 – 4)2 is :
- A
380
- B
480
- C
400
- D
525
Solution
If both the mean and the standard deviation of 50 observations x1, x2, ... x50 are equal to 16, then the mean of (x1 – 4)2, (x2 – 4)2, ... (x50 – 4)2 is :
380
480
400
525