JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

If the tangent to the curve $y = \frac{x}{x ^{2} - 3}, x \in R,$ $(x \neq = \pm 3)$ at a point ( $α$ , $β$ ) $\neq =$ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0, then :

A
|6 $α$ + 2 $β$ | = 19
B
|2 $α$ + 6 $β$ | = 19
C
|6 $α$ + 2 $β$ | = 9
D
|2 $α$ + 6 $β$ | = 11

Solution

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