JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

The integral $\int \frac{2 x ^{3} - 1}{x ^{4} + x} d x$ is equal to : (Here C is a constant of integration)

A
$lo g_{e} \frac{x ^{3} + 1}{x} + C$
B
$\frac{1}{2} lo g_{e} \frac{( x ^{3} + 1 ) ^{2}}{∣ x ^{3} ∣} + C$
C
$\frac{1}{2} lo g_{e} \frac{x ^{3} + 1}{x ^{2}} + C$
D
$lo g_{e} \frac{x ^{3} + 1}{x ^{2}} + C$

Solution

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