JEE Main2019Math
Q.
If the plane 2x – y + 2z + 3 = 0 has the distances and units from the planes 4x – 2y + 4z + = 0 and 2x – y + 2z + = 0, respectively, then the maximum value of + is equal to :
- A
13
- B
15
- C
5
- D
9
Solution

If the plane 2x – y + 2z + 3 = 0 has the distances and units from the planes 4x – 2y + 4z + = 0 and 2x – y + 2z + = 0, respectively, then the maximum value of + is equal to :
13
15
5
9
