JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

The value of $sin^{- 1} (\frac{12}{13}) - sin^{- 1} (\frac{3}{5})$ is equal to :

A
$\frac{π}{2} - sin^{- 1} (\frac{56}{65})$
B
$π - sin^{- 1} (\frac{63}{65})$
C
$π - cos^{- 1} (\frac{33}{65})$
D
$\frac{π}{2} - cos^{- 1} (\frac{9}{65})$

Solution

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