JEE Main 2019 — Math solution | Fundamenthol

JEE Main2019Math

Q.

For $x \in (0, \frac{3}{2})$ , let f(x) = $x$ , g(x) = tan x and $h (x) = \frac{1 - x ^{2}}{1 + x ^{2}} .$ if If $ϕ$ (x) = ((hof)og)(x), then $ϕ (\frac{π}{3})$ is equal to :

A
$tan \frac{5 π}{12}$
B
$tan \frac{π}{12}$
C
$tan \frac{11 π}{12}$
D
$tan \frac{7 π}{12}$

Solution

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