JEE Main 2019 — Physics solution

JEE Main2019Physics

n moles of an ideal gas with constant volume heat capacity C_V undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is :

A
$\frac{4nR}{C _{V} + nR}$
B
$\frac{R}{C _{V} + nR}$
C
$\frac{4nR}{C _{V} - nR}$
D
$\frac{nR}{C _{V} - nR}$

Solution

For Isobaric process

Work done (W) = $nRΔT$

and Heat given (Q) = $n C_{P} ΔT$

$∴ \frac{W}{Q} = \frac{R}{C _{P}} = \frac{R}{C _{V} + R}$

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