JEE Main 2019 — Physics solution

JEE Main2019Physics

An electromagnetic wave is represented by the electric field $E = E_{0} \overset{n}{^} sin [ω t + (6y - 8z)] .$ Taking unit vectors in x, y and z directions to be $\hat{i}, \hat{j}, \hat{k},$ the direction of propogation $\overset{s}{^}$ , is :

A
$\overset{s}{^} = (\frac{- 3 j ^ + 4 k ^}{5})$
B
$\overset{s}{^} = (\frac{3 i ^ - 4 j ^}{5})$
C
$\overset{s}{^} = (\frac{- 4 k ^ + 3 j ^}{5})$
D
$\overset{s}{^} = (\frac{4 j ^ - 3 k ^}{5})$

Solution

$E = E_{0} sin (ω t + 6 y - 8 z) \overset{s}{^} = \frac{8 k ^ - 6 j ^}{10} = (\frac{4 k ^ - 3 j ^}{5})$

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