JEE Main2019Physics
Q.
An excited He+ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength , energy ):
- A
n = 5
- B
n = 7
- C
n = 4
- D
n = 6
Solution

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