JEE Main 2019 — Physics solution | Fundamenthol

JEE Main2019Physics

Q.

The trajectory of a projectile near the surface of the earth is given as y = 2x – 9x². If it were launched at an angle $θ$ ₀ with speed v₀ then (g = 10 ms^–2):

A
$θ_{0} = sin^{- 1} (\frac{1}{5})$ and $v_{0} = \frac{5}{3} m s^{- 1}$
B
$θ_{0} = cos^{- 1} (\frac{2}{5})$ and $v_{0} = \frac{3}{5} m s^{- 1}$
C
$θ_{0} = cos^{- 1} (\frac{1}{5})$ and $v_{0} = \frac{5}{3} m s^{- 1}$
D
$θ_{0} = sin^{- 1} (\frac{2}{5})$ and $v_{0} = \frac{3}{5} m s^{- 1}$

Solution

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