JEE Main 2019 — Physics solution

JEE Main2019Physics

A man (mass = 50 kg) and his son (mass = 20 kg) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of 0.70 ms^–1 with respect to the man. The speed of the man with respect to the surface is :

A
0.20 ms^–1
B
0.14 ms^–1
C
0.47 ms^–1
D
0.28 ms^–1

Solution

$50 V_{1} = 20 V_{2} V_{1} + V_{2} = 0.70 V_{1} = 0.20$

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