JEE Main 2025 Apr 2 Shift 1, Physics Q18: Properties of Fluids

JEE Main2025Apr 2, Shift 1Physics

Match List–I with List–II.

Choose the correct answer from the options given below :

Solution

Work out each quantity's dimensions from its definition.

(A) Coefficient of viscosity: from $F = η A \frac{d v}{d y}$ ,

$[η] = \frac{[ F ]}{[ A ] [ d v / d y ]} = \frac{M L T ^{- 2}}{L ^{2} \cdot T ^{- 1}} = M L^{- 1} T^{- 1}$ $\Rightarrow$ (IV).

(B) Intensity of wave: power per unit area, $[I] = \frac{M L ^{2} T ^{- 3}}{L ^{2}} = M L^{0} T^{- 3}$ $\Rightarrow$ (I).

(C) Pressure gradient: $\frac{d P}{d x}$ , $\frac{M L ^{- 1} T ^{- 2}}{L} = M L^{- 2} T^{- 2}$ $\Rightarrow$ (II).

(D) Compressibility: reciprocal of bulk modulus, $\frac{1}{P} = M^{- 1} L T^{2}$ $\Rightarrow$ (III).

So (A)–(IV), (B)–(I), (C)–(II), (D)–(III), matching option (2).

Concept behind this question

Concept-wise practice with instant solutions on Fundamenthol.