JEE Main 2025 Apr 3 Shift 1, Physics Q22: Magnetic Force on Current Carrying Wires

JEE Main2025Apr 3, Shift 1Physics

Q.

A 4.0 cm long straight wire carrying a current of 8 A is placed perpendicular to an uniform magnetic field of strength 0.15 T. The magnetic force on the wire is ________ mN.

Your answer

Solution

For a current-carrying wire perpendicular to $B$ :

$F = B I L = 0.15 \times 8 \times 0.04 = 0.048 N = 48 mN .$

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