JEE Main 2025 Apr 3 Shift 1, Chemistry Q22: Stoichiometry

JEE Main2025Apr 3, Shift 1Chemistry

0.5 g of an organic compound on combustion gave 1.46 g of $CO_{2}$ and 0.9 g of $H_{2} O$ . The percentage of carbon in the compound is ____. (Nearest integer)

[Given : Molar mass (in g mol $^{- 1}$ ) C : 12, H : 1, O : 16]

Your answer

Solution

All carbon in the organic compound ends up as $CO_{2}$ . By POAC on carbon:

$mass of C = \frac{12}{44} \times mass of CO_{2} = \frac{12}{44} \times 1.46 \approx 0.398 g .$

Percentage of carbon:

$% C = \frac{0.398}{0.5} \times 100 \approx 79.6%.$

Rounded to the nearest integer, $% C = 80$ .

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JEE Main 2025 Apr 3 Shift 1, Chemistry Q22: Stoichiometry

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