JEE Main 2025 Apr 3 Shift 2, Physics Q9: Wave Optics

JEE Main2025Apr 3, Shift 2Physics

A monochromatic light of frequency $5 \times 1 0^{14}$ Hz travelling through air, is incident on a medium of refractive index ' $2$ '. Wavelength of the refracted light will be :

A
$300$ nm
B
$600$ nm
C
$400$ nm
D
$500$ nm

Solution

Frequency is unchanged on refraction; speed in the medium is $v = c / μ$ , so the wavelength in the medium is

$λ_{m} = \frac{v}{f} = \frac{c}{μ f} = \frac{3 \times 1 0 ^{8}}{2 \times 5 \times 1 0 ^{14}} = 3 \times 1 0^{- 7}$ m $= 300$ nm.

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