JEE Main 2025 Apr 3 Shift 2, Chemistry Q5: Quantum Numbers

JEE Main2025Apr 3, Shift 2Chemistry

For electron in '2s' and '2p' orbitals, the orbital angular momentum values, respectively are :

Solution

Orbital angular momentum is given by $L = ℓ (ℓ + 1) \frac{h}{2 π}$ , where $ℓ$ is the azimuthal quantum number.

For a 2s electron, $ℓ = 0$ , giving $L = 0$ .

For a 2p electron, $ℓ = 1$ , giving $L = 1 \cdot 2 \frac{h}{2 π} = 2 \frac{h}{2 π}$ .

$∴$ The pair $(0, 2 h /2 π)$ matches option (4).

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