JEE Main 2025 Apr 4 Shift 1, Chemistry Q1: Colligative Properties

JEE Main2025Apr 4, Shift 1Chemistry

XY is the membrane / partition between two chambers 1 and 2 containing sugar solutions of concentration $c_{1}$ and $c_{2}$ ( $c_{1} > c_{2}$ ) mol L $^{- 1}$ . For the reverse osmosis to take place identify the correct condition

(Here $p_{1}$ and $p_{2}$ are pressures applied on chamber 1 and 2)

(A) Membrane/Partition ; Cellophane, $p_{1} > π$

(B) Membrane/Partition ; Porous. $p_{2} > π$

(D) Membrane/Partition : Cellophane, $p_{2} > π$

Choose the correct answer from the option given below :

A
B and D only
B
A and D only
C
A and C only
D
C only

Solution

Reverse osmosis requires (i) a semipermeable membrane such as cellophane or parchment paper (porous membranes will not work, since they allow free passage of solute as well), and (ii) external pressure on the more concentrated side that exceeds the osmotic pressure $π$ .

Since $c_{1} > c_{2}$ , chamber 1 is the more concentrated side. The required driving condition is therefore $p_{1} > π$ .

Combining both requirements, the valid options are (A) cellophane with $p_{1} > π$ and (C) parchment paper with $p_{1} > π$ .

$∴$ Correct choice: A and C only.

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JEE Main 2025 Apr 4 Shift 1, Chemistry Q1: Colligative Properties

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