JEE Main 2025 Apr 7 Shift 2, Chemistry Q13: Vapour Pressure Of A Solution
Match List-I with List-II
| List-I | List-II |
|---|---|
| (A) Solution of chloroform and acetone | (I) Minimum boiling azeotrope |
| (B) Solution of ethanol and water | (II) Dimerizes |
| (C) Solution of benzene and toluene | (III) Maximum boiling azeotrope |
| (D) Solution of acetic acid in benzene | (IV) = 0 |
Choose the correct answer from the options given below :
- A
(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- B
(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- C
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- D
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Chloroform and acetone show negative deviation from Raoult's law due to hydrogen bonding between the CHCl H and the acetone C=O oxygen; strong negative deviation produces a maximum boiling azeotrope, so (A) (III).
Ethanol and water show positive deviation, since mixing partially disrupts the extensive hydrogen bonding of the pure liquids; this produces a minimum boiling azeotrope, so (B) (I).
Benzene and toluene are structurally very similar with comparable intermolecular forces, forming a near-ideal solution with , so (C) (IV).
Acetic acid in a non-polar solvent like benzene associates through hydrogen bonding to form a cyclic dimer, so (D) (II).
Concept behind this question
Vapour Pressure Of A SolutionNotes, formulas and examples →More previous year questions on Vapour Pressure Of A Solution
Practice more Chemistry
Concept-wise practice with instant solutions on Fundamenthol.
Start practicing →