JEE Main 2025 Jan 22 Shift 1, Chemistry Q16: Colour, Magnetism And Stability Of Co-ordination Compounds
JEE Main2025Jan 22, Shift 1Chemistry
Q.
In which of the following complexes the CFSE, will be equal to zero?
- A
[Fe(NH)]Br
- B
[Fe(en)]Cl
- C
K[Fe(CN)]
- D
K[Fe(SCN)]
Solution
In K[Fe(SCN)], Fe is in the +3 state with configuration. SCN (N-bonded thiocyanate) acts as a weak-field ligand, giving a high-spin arrangement: .
CFSE .
The other complexes ([Fe(NH)] is ; [Fe(en)] is low-spin with en a moderate field; [Fe(CN)] is low-spin ) all have non-zero CFSE.
Concept behind this question
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