JEE Main 2025 Jan 22 Shift 2, Physics Q14: Work Energy Theorem And Its Applications

JEE Main2025Jan 22, Shift 2Physics

A force $F = 2 \hat{i} + b \hat{j} + \hat{k}$ is applied on a particle and it undergoes a displacement $\hat{i} - 2 \hat{j} - \hat{k}$ . What will be the value of b, if work done on the particle is zero.

A
0
B
$\frac{1}{2}$
C
$\frac{1}{3}$
D
2

Solution

Work done $W = F \cdot S$ .

$W = (2) (1) + (b) (- 2) + (1) (- 1) = 2 - 2 b - 1 = 1 - 2 b$ .

Setting $W = 0$ : $1 - 2 b = 0 \Rightarrow b = \frac{1}{2}$ .

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JEE Main 2025 Jan 22 Shift 2, Physics Q14: Work Energy Theorem And Its Applications

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