JEE Main 2025 Jan 23 Shift 1, Physics Q16: Units And Dimensions

Each term on the right of $\varphi =\alpha \sigma +\beta \lambda$ must individually carry the dimensions of electric flux. Hence $[\alpha ]=\frac{[\varphi ]}{[\sigma ]}$ and $[\beta ]=\frac{[\varphi ]}{[\lambda ]}$.

$\frac{[\alpha ]}{[\beta ]}=\frac{[\lambda ]}{[\sigma ]}=\frac{\text{Q/L}}{{\text{Q/L}}^2}=L$.

A length is a displacement. $\therefore$ The ratio represents displacement.