JEE Main 2025 Jan 23 Shift 1, Chemistry Q3: Group 16 Elements: The Oxygen Family

JEE Main2025Jan 23, Shift 1Chemistry

The incorrect statements among the following is

Solution

Sulfur in $S O_{2}$ is in the +4 oxidation state, which is intermediate between $- 2$ and $+ 6$ . This allows $S O_{2}$ to behave both ways:

As a reducing agent (S going from +4 to +6): $S O_{2} + 2 H_{2} O + C l_{2} \to H_{2} S O_{4} + 2 H C l$ .

As an oxidising agent (S going from +4 to 0): $S O_{2} + 2 H_{2} S \to 3 S + 2 H_{2} O$ .

$∴$ Statement (4) is incorrect.

Concept behind this question

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